支持向量机-软间隔SVM

定义

$$
\begin{aligned}
&\lbrace\left(x_{i}, y_{i}\right)\rbrace_{i=1}^{N}\\
&x_{i} \in \mathbb{R}^{p}, \quad y_{i} \in \lbrace -1,+1\rbrace
\end{aligned}
$$

$$\min \frac{1}{2} w^{\top} w+\operatorname{loss}$$

  1. $$loss =\sum_{i=1}^{N} I\left\lbrace_{i}\left(w^{\top} x_{i}+b\right)<1\right\rbrace$$
  2. $loss:$距离
    $$
    \begin{aligned}
    &\text{如果}\ y_{i}\left(w^{\top} x_{i}+b\right) \geqslant 1, \quad \text {loss} = 0\\
    &\text{如果}\ y_{i}\left(w^{\top} x_{i}+b\right)<1, \quad \text { loss }=1-y_{i}\left(w^{\top} x_{i}+b\right)
    \end{aligned}
    $$

$$\operatorname{loss}= \max \left\lbrace 0,1-{y_{i}\left(w^{\top} x_{i}+b\right)}\right\rbrace$$

\begin{cases}
\min_{w, b} \frac{1}{2} w^{\top} w+C \sum_{i=1}^{N} \max \left\lbrace 0,1-y_{i}(w^{\top} x_{i}+b)\right\rbrace \\
\text { s.t. } y_{i}\left(w^{\top} x_{i}+b\right) \geqslant 1
\end{cases}

引入$\xi_{i}=1-y_{i}\left(w^{T} x_{i}+b\right), \quad \xi_{i} \geqslant 0$
\begin{cases}
\min_{w, b} \frac{1}{2} w^{T} w+C\sum_{i=1}^{N} \xi_{i} \\
\text { s.t. } y_{i}\left(w^{\top} x_{i}+b\right) \geqslant 1-\xi_{i} \quad \xi_i \geq 0\\
\end{cases}

非常感谢各位老板投喂!